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But using %lu solved the issue

Actually, rather than focusing on the problem and the line of codes, i want to know about the difference between %ul and %lu Maybe i could figure out what's wrong Searching doesn't give me something useful (except that they are different) Any explanation or link/reference is appreciated. 9 what is the difference between %zu and %lu in string formatting in c %lu is used for unsigned long values and %zu is used for size_t values, but in practice, size_t is just an unsigned long

Cppcheck complains about it, but both work for both types in my experience. I know there is a very similar question and answer on stackoverflow (here), but this seems to be distinctly different I am using statsmodels v 0.13.2, and i am using an arima model as opposed to a Lu decomposition error using sarimax in statsmodels asked 5 years, 2 months ago modified 3 years, 4 months ago viewed 4k times When i print the number using the format specifier %llu, what is printed is %lu I also compare the value i get from atoll or strtoll with the expected value and it is smaller, which i guess shows that an overflow has occurred

Why does an overflow occur if the number fits in a u64 variable

The number for example is 946688831000. The printf function takes an argument type, such as %d or %i for a signed int However, i don't see anything for a long value. Lu decomposition without pivoting is rarely seen in practice It's primarily used to introduced people to the idea of the technique, then the introduction builds by introducing pivoting. Guid technically stands for globally unique identifier

What it is, actually, is a 128 bit structure that is unlikely to ever repeat or create a collision If you do the maths, the domain of values is in the undecillions Use guids when you have multiple independent systems or clients generating id's that need to be unique For example, if i have 5 client apps creating and inserting. Conventional wisdom states that if you are solving ax = b several times with the same a and a different b, you should be using an lu factorization for lu If i use p, l, u = scipy.linalg.lu(a) and.

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