Return the minimum number of refueling stops the car must make in order to reach its destination Since this problem is asking for the least amount of refuelings, we should attempt a greedy approach to the solution To accomplish that, we should start with 0 refuelings and keep attempting one additional refueling until we find a working solution. The code handles this elegantly by appending [target, 0] to the stations list This treats the destination as a final checkpoint with no fuel, ensuring we verify we can reach it. How to prove that refilling at farthest reachable gas is a safe move
Are there any alternatives to writing the same code but using for loop (in short, i understood the logic but i am not able to compute it) any resources/help/hint/guidance is greatly appreciated! At points 375 and 750 This is the minimum number of refills as with a single refill One would only be able to travel at most 800 miles One cannot reach the gas station at point 9 as the previous gas station is too far away
The problem sounds like this You are going to travel to another city that is located 𝑑 miles away from your home city Your car can travel at most 𝑚 miles on a full tank and you start with a full tank. What is the least number of refueling stops the car must make in. What is the least number of refueling stops the car must make in order to reach its destination The car has to compulsorily stop at m petrol tanks whose distance from the starting position is given as m integers
The task is to find the number of times, the car has to refill its tank including the compulsory stops to complete its journey of n km.
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